eachRight()

eachRight<T>(collection, iteratee): void

Iterates over elements of collection from right to left.

DEPRECATED

Use [...array].reverse().forEach() directly instead.

---

Type Parameters

T: T

The type of elements in the collection.

---

Parameters

collection: readonly T[]

The collection to iterate over.

iteratee: (value, index, collection) => void

The function invoked per iteration.

---

Returns: void

---

Since

---

See Also

Array.forEach() - MDN 2.0.0

---

Also known as

forEachRight (Lodash, es-toolkit) · ❌ (Remeda, Radashi, Ramda, Effect, Modern Dash, Antfu)

---

Example

// ❌ Deprecated approach
eachRight([1, 2, 3], x => console.log(x));
// logs: 3, 2, 1

// ✅ Recommended approach
[...[1, 2, 3]].reverse().forEach(x => console.log(x));
// logs: 3, 2, 1

---

How it works?

Iterates over elements from right to left. Deprecated: Use array.reverse().forEach() or loop backward.

Native Equivalent

// ❌ eachRight(arr, fn)
// ✅ [...arr].reverse().forEach(fn)
// ✅ for (let i = arr.length - 1; i >= 0; i--) fn(arr[i])

---

Use Cases

Iterate in reverse 📌

Process array elements from end to start.

#iterate#reverse#backwards#each

const items = [1, 2, 3];
[...items].reverse().forEach(item => console.log(item));
// => 3, 2, 1

Process stack order

Handle items in LIFO order.

#process#stack#LIFO#order

const stack = ["first", "second", "third"];
for (let i = stack.length - 1; i >= 0; i--) {
  process(stack[i]);
}

Undo in reverse order

Apply undo operations in reverse.

#undo#reverse#history#actions

const history = [action1, action2, action3];
history.reduceRight((_, action) => action.undo(), null);